# The velocity of particle moving along a straight line increases according to the law#v=v_0+Kx# , where K is a positive constant,then options are below?

##
- the acceleration of the particle is
#K(v_0+Kx)#
- the particle takes a time
#(1/k)*ln(v/v_0)# to attain speed of v
- velocity varies linearly with displacement with slope of velocity-displacement curve equal to K.
- all of the above

~correct option given is 4(help me)

- the acceleration of the particle is
#K(v_0+Kx)# - the particle takes a time
#(1/k)*ln(v/v_0)# to attain speed of v - velocity varies linearly with displacement with slope of velocity-displacement curve equal to K.
- all of the above

~correct option given is 4(help me)

##### 1 Answer

Jul 2, 2018

Above three options are correct

#### Explanation:

Given the velocity of particle as a function of displacement

(1) The acceleration

(2). We know that the velocity

(3) Slope of velocity